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## Answers

1st term = cube of the first term of the factors = x³

2nd term = thrice the product of the square of the first term and second term of the factors = 3[(x²)(6)]

3rd term = thrice the product of the square of the second term and the first term = 3[(x)(6)²]

4th term = cube of the second term = 6³

SOLUTION:

(x+6)³ = (x)³ + 3[(x²)(6)] + 3[(x)(6)²] + 6³ =

**x**

**³ + 18x² + 108x + 216**

Remember that the answer of the cube of a binomial has always 4 terms.