Answers

2016-07-09T20:09:56+08:00
(k+1)/(k-3) = (4k-2)/(k+1)

(k+1)^2 = 4k^2 - 14k + 6

k^2 + 2k +1 = 4k^2 - 14k + 6

= 3k^2 - 16k + 5

Use the quadratic formula,

-b
±√ b^2 - 4ac   /  2a

16
±√ 256 - (4)(3)(5)   /  2(3)

16
±√ 256 - 60   / 6

16
±√ 196  / 6

16
± 14  / 6

16 + 14  / 6 = 30/6 = 5

16 - 14  / 6 = 2/6 = 1/3

Therefore, k=1/3 or k=5
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