Answers

The Brainliest Answer!
2016-06-29T18:02:36+08:00
If y>0, then x2 = y has two real solution or roots. x = ±√y
If y=0, then x2 = y has one real solution. 

TWO REAL SOLUTIONS

1. x
2 - 25 = 0
→ x2 - 25 + 25 = 0 + 25
→ x2 = 25 → x = ±√25
x = ± 5

2. t2 + 16
→ √t2 = √16
→ t = ±4

ONE REAL SOLUTION

1. k2 = 0
→ to check, k2 = 0
0 = 0

2. g2 = 0
→  to check, g2 = 0
0 = 0

NO REAL SOLUTION

1. s2 + 9 = 0.
Write the equation in the form x2 = y.
s2 + 9 = 0 → s2 + 9 - 9 = 0 - 9
s2 = -9

2. g2 = 16 = 0
g2 = 16 = 0 → g2 + 16 - 16 = 0 - 16
g2 = -16
1 5 1
NO REAL SOLUTION
s + 9 = 0. Write the equation in the form x2 = k.
s2 + 9 = 0 → s2 + 9 - 9 = 0 - 9 → s2 = -9
thank you very much it help me a lot