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The sum of the first 10 terns of an arithmetic sequence is 530.What is the first term if the last term is 80? What is the common difference? with solution

Use the formula: a sub n= a sub 1 + (n-1)d ; where in a sub n is the last term, a sub 1 is the 1st term, n is the number of terms, and d is the common difference.

or use the formula: Sum of the terms= n/2 (2 a sub 1 + (n-1)d) or Sum of the terms= n/2 (a sub 1 + a sub n)

use the second sum formula.. 530=10/2 (a sub 1 + 80) 530= 5 (a sub 1 + 80) 530= 5(a sub 1) + 400 530-400= 5(a sub 1) 130= 5 (a sub 1) 130/5= a sub 1 26= a sub 1

the first term is 26. now u have the first term...