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The sum of the first 35 terms of an arithmetic sequence is 8,365 what term if the last terms is 460?what is the common difference?

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460=8,365+(35-1)d
460=8,365+34d
460-8,365=34d
-7905÷34=34d÷34
D= -2325

A1= ?

D=?

An= 460

Sn= n/2 (a1+an)

8,365=35/2 (a1+ 460)

8,365= 17.5 (a1+460)

8,365= 17.5a1 + 8,050

8,365-8,050= 17.5a1

315=17.5a1

We divided it by 17.5 so the answer is

18=a1

18 is the first term.

We are going to find the common difference next.

An=a1+(n-1)d

460= 18+(35-1)d

460= 18+34d

460-18=34d

442=34d

We divided it by 34. So the answer is

13=D

First term is 18

Common difference is 13