Answers

2014-07-21T12:53:34+08:00
N203
N=14,0=16

Mr N2O3
=(AI N x Ar N)+(AI O x Ar O)
=(2 x 14) + (3 x 16)
=28+48
=76
0
2014-07-21T20:59:36+08:00
N2O3

N=14
O=16

N= 14 X 2 = 28
O= 16 X 3 = 48
 
Add the sum Of N and O
28 + 48 = 76 g/mol
0