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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Three positive numbers form a geometric sequence. if the geometric mean of two numbers is 6 and the geometric mean of the last two terms is 24, find the

√(A₁ x A₂) = 6 √(A₂ x A₃) = 24 *Transform both equations so that A₂ will be left on one side. *Square both sides then divide by A₁/A₃ A₂= 36/A₁ A₂= 576/A₃ therefore, 36/A₁ = 576/A₃ *Going back to the fomula for finding An A₃=A₁r² *Substitute 36/A₁ = 576/A₁r² *Multiply both sides by A₁r² 36r² = 576 r² = 16 r=+/- 4 *Since al terms are positive then tha common ratio is 4. *The geometric mean of the two given numbers would be the second term which is 12. by that, you can tel what are the three terms. 3, 12, 48