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The area of a triangle is 24m², and the base is as long as the altitude. find the base and the altitude

2
by nicx31

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by nicx31

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=1\2 2h(h)

=1\2 (2h^)

24m^=10.5h^

24m^=10.5h^\2

24m^=5.25h^

24m^=5.25times2

24m^=10.20base

= 1/2 (b . b) since the base is the same as the heigth

= 1/2 * b²

24 = 1/2b²

b² = 48

b = √48

~ 6.928m

so the base or attitude is ~ 6.928m