# The resultant of the concurrent force show is 300lb pointing up along the y-axis.compute the values of f and theta required to give the resultant

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by orejfrando

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by orejfrando

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@2nd quad;

Fx=-f (cos 45);=-f(1/squaroot of2)=-0.707f;

Fy=f (sin45); =f(1/squaroot of 2)=0.707f;

@1st quadrant

Fx=f(cos45);=0.707f

Fy=f(sin45);=0.707f

since they are in same direction, let us add all fx components and fy components:

fx(total)= 0.707f-0.707f=0

fy(total)= 0.707f+0.707f=1.414f;

Resultant) R^2= fx^2+fy^2

300^2=0 +[1.414f]^2

90,000=2f^2;

f^2=45,000;

f=212.13 lbs..@ 45 degrees south east

f=212.13 lbs..@45 degrees south west