Hi, I'm having a bit of trouble with my math problem.

The topic is about solving quadratic equations through factoring.
And here's the equation:

15x^2 = 2(4 - 7x)
I distributed the 2

⇒ 15x^2 = 8 - 14x
and then transformed it into the standard form and got


⇒ 15x^2 + 14x - 8 = 0
Then I factored it out into:

⇒ 15x^2 + 20x - 6x - 8 = 0
then I grouped the terms
⇒ (15x^2 + 20x) - (6x - 8) = 0
factored them out again.
⇒ 5(3x + 4) - 2(3x - 4) = 0

And that's where I'm lost. I don't know what to do next since the two factors are conjugates. I hope someone can help. :)

2

Answers

The Brainliest Answer!
2014-07-21T22:17:11+08:00
15x^2+20x-6x-8
5x(3x+4)-2(3x+4)
(3x+4)(5x-2) ^^
1 5 1
right?
Oh yes! You're right, I'm forgetting the real process of factoring out. Let me see if I got that clear.
instead of

(15x^2+20)-(6x-8)
:)
*continuing*
I can say (15x^2+20)(-6x-8)
thus -6 and -8 would have a common factor of negative two, and will be left with positive 3x+4.
yep
2014-07-22T10:03:49+08:00
15x+20-10x+8
(15x-10x)+(20+8)
5x=28
0