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In derivation f(x)=x^2 ( please see theorem of derivatives )
                    f '(x)    =2 x^2-1 =  2x...answer..
solving this by definition....when limit of h=0

f '(x)= {(x + h)^2-x^2]/h
      = [x^2 + 2xh +h^2-x^2]/h
      = [2xh +h^2]/ h
     factor  h;
      =[h (2x +h)]/h...cancel h
      = 2x + h
when h limit is 0
     = 2x + 0

 f '(x)= 2x....answer... please do it the second problem , this will be your guide, kid...
0 0 0
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