1. What must be the value of k so that 5k-3, k+2, and 3k-11 will form an arithmetic sequence?
2. which term of the arithmetic sequence whose first term is -3,common difference is 2, and last term is 23?
3. find a sub 1 if a sub 8=54 and a sub 9=60.
4. find the 9th term of the arithmetic sequence with asub1 =10 and d= -1/2
5. give the arithmetic sequence of 5 terms if the first term is 8 and the last term is 100.



1. k=3
3. a sub 1 = 12
4. 9th term= 6
1 5 1
I need solution too please
For number 1: m-1=2-m that's the solution. Where m is the Mean or the middle term.
For number 3: an=a1+(n-1)d is the solution. Where an is the last term, n is the number of term used in the last term and d is the common difference.
Number 4 is the same with number 3: an=a1+(n-1)d where a1 is the first term which is 10, n is the specific term that you are finding which is 9 and d as the common difference which is -½