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2014-07-22T22:38:04+08:00

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If x is the side of the triangle then its altitude should be  \frac{ \sqrt{3} }{2} x (from the property of 30-60-90 triangle)

Altitude: x-2  (is 2 cm shorter than its side)

x-2= \frac{ \sqrt{3} }{2}x \\  \\ 2x-4= \sqrt{3}x \\  \\ (2- \sqrt{3})x=4 \\  \\ x= \frac{4}{2-\sqrt{3} }=\boxed{8+4 \sqrt{3}}


Length of side = 8+4 \sqrt{3} cm

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Thank you! Thank you! So much! :D
2014-07-23T14:10:37+08:00

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The answer is   8+4 \sqrt{3] cm

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