Answers

2016-07-09T14:49:49+08:00
Ammonia is a Base, use the value of its Kb to get the pOH. But first, establish a Base Dissociation Equation since it is a Weak base.

kb = ([NH4+][OH-])/[NH3]

Use the Ice Table to arrive to an equation.

1.8 x 10^-5 = x^2/ 0.01 (assuming 0.01 - x is equivalent to 0.01)

x = 4.24 x 10^-4 [OH]-

pOH = -log [OH]
         = 3.37

pH= 14 - pOH = 10.62
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