Answers

2016-07-11T20:14:18+08:00
4s^2-12s+9=0
(2s-3) (2s-3)
1 5 1
2016-07-11T20:28:00+08:00
You transpose 12s to the other side to become 4s²-12s+9=0,so the factor of that is (2s-3)(2s-3),then we go to solve the x sub 1 and x sub 2 see below



4s²+9=12s
4s²-12s+9=0
(2s-3)(2s-3)=0
x sub 1
2s-3=0
2s=3
2s/2=3/2
s=3/2


x sub 2
2s-3=0
2s=3
2s/2=3/2
s=3/2
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