Answers

2016-07-14T20:55:45+08:00
2y (y-2) = (y + 1)(y - 6) (-2)
2y^2 - 4y = (y + 1) (-2y + 12)
2y^2 - 4y = -2y^2 + 12y - 2y + 12
2y^2 - 4y = -2y^2 + 10y + 12
2y^2 + 2y^2 - 4y + 10y + 12 = 0
4y^2 -14y - 12 =0

a=4  b=-14  c=-12
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