Answers

2016-07-15T16:19:47+08:00
K and 1/k [1]

a sub n = a sub 1 (r raise to n-1)

1/k = k (r^2)
k[1/k=kr^2]k
1=k^2r^2
1/k^2=r^2
_/r^2 = _/1/k^2
common ratio=1/k

Formula again.

1/k=a sub 1 (1/k)
k[1/k=a sub 1 (1/k)]k
a sub 1 =1


Ans. Geometric mean between k and 1/k is 1.

Final ans. is 1
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