Let's solve this with algebra.
so there is a 3 digit number right?
let's name that xyz
we already have a value for x which is 9
Now. you said that x is 3 more than z
that would be 9=z+3
can you guess what Z is now??? (I'm going to leave that for you.)
then you also said that x is 5 more than the tens(y)
and that would be.. 9=y+5
now, can you guess what y is now???
it's already obvious, but we can systematically solve it using the subtraction property of equality right?
1. z+3 = 9 subtract 3 on both sides
z +3 -3 = 9 - 3 finish the solution
z +0 = 6
z = 6
2. y+5 = 9 do the same process, subtract on both sides
y +5 -5 = 9-5
y + 0 = 4
y = 4
Thus the answer would be 964
explanation: We used the SPE.
hope it helped! :))