Answers

2016-07-20T23:42:04+08:00
K+2-(3k-1)=3k-1-(7k-12)
k+2-3k+1=3k-1-7k+12
-2k+3=-4k+11 then transpose.
-2k+4k=11-3
2k=8 divide both side by 2.
k=4 then substitute.
(4)+2=6
3(4)-1=11
7(4)-12=16
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