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Make it sure if that 10km is in 'distance ' or speed?
1 5 1
ok, so this would be, time1+time2=1.33hrs(1hr and 20min);time1=distance/speed1; time2=distance/speed2; note ;d=d or 5/speed+5/10=1.33; 5/speed=1.33-0.5; speed=5/.833=6kph
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