Answers

  • Brainly User
2016-07-21T13:37:19+08:00
The missing terms are a₂, a₃, a₄, a₅.

First, find the common ratio (r):

an = a₁  (r)^{n-1}

an/a₆ = 486         a₁ = -2       n = 6

486 = -2 (r)⁶⁻¹

486 = -2 (r⁵)

  486         -2(r⁵)
-------  =   --------
    -2           -2

-243 = r⁵

 \sqrt[5]{r} = \sqrt[5]{-243}

r = - 3    ⇒  common ratio

Solve for the missing terms:

a₂ = a₁ (r)
a₂ = -2 (-3)
a₂ = 6

a₃ = a₂ (r)
a₃ = 6 (-3)
a₃ = -18

a₄ = a₃ (r)
a₄ = -18 (-3)
a₄ = 54

a₅ = a₄ (r)
a₅ = 54 (-3)
a₅ = - 162

ANSWER:  6,   -18,   54,   -162

The geometric sequence is -2,  6,  -18,   54,   -162,   486

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