Reverse pala :( why -sinx = (cot x - csc x)(cos x +1) ? solution for -sinx, using trigonometric identities

Anong reverse pala?
wala po un . basta solve -sinx ,
need kopo solution salamat:)
Kailangan i-prove yung equation?
oo , ano ung gagawin sa -sinx para makuha (cot x - csc x) (cosx +1) , solution ung kailangan ko



This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
-sinx = (cotx-cscx)(cosx+1) \\  \\ -sinx = ( \frac{cosx}{sinx} - \frac{1}{sinx})(cosx+1) \\  \\ -sinx = (\frac{cosx-1}{sinx})(cosx+1) \\  \\ -sinx = \frac{cos^2x-1}{sinx} \\  \\ -sinx = \frac{-sin^2x}{sinx} \\  \\ -sinx =-sinx

Identity used:
from 4th line to 5th line:  sin²x + cos²x = 1

pero ung hinahanap ko . isolve ung -sinx .
anu ung isasubtitute mo sa -sinx . gets?
Di ko gets. Usually kasi pag gantong problem, yung mas complicated na side ang i-mamanipulate para maging simple. Yung gusto mo naman ay yung simplest side and i-manipulate para maging complicated?
oo ganon . ganon ung homewwork na pinagawa . ginawa kona kasi ung mas complicated na side . tapos baliktad namn yung simplest side nman ung i mamanipulate
May in-attach akong ibang solution. Tignan mo kung ok na
tatanong namn prof, ko kung pano nakuha ung -sin^2x ? pano nakuha un?