What is the answer for equation transformable to quadratic equation
1. x(x+3)=28
2. 3s(s-2)=12s
3. (t+1) squared + (t-8) squared + 45
4. (3r+1) squared + (r+2) squared = 65
5. (x+2) squared + (x-2) squared = 16
5 3 3

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number 5 is (x+2)squared /over 5 and the (x-2)squared /over 3 and 16/3... with solution thanks :)

Answers

2016-07-26T19:36:43+08:00
1.x squared+3x=28
x squared+3x-28=0
2.3s squared-6s=12s
3s squared-6s-12s
3s squared-18s=0
3.t squared+2t+1+t squared-16t+64+45
2t squared-14t+110=0
4.9r squared+6r+1+r squared+4r+4=65
10r squared+10r+5=65
10r squared+10r+5-65=0
10r squared+10r-60=0
try to solve no.5
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