Answers

2016-07-31T17:28:33+08:00
The center lies in the intersection of 2y = 3x and the line tangent to it which could be identified as x = 4 since the coordinates are (4,0)
since x = 4; we could imply that 2y = 3(4); 2y = 12; y = 6
we now have the center of the circle (4,6)
circle equation: (x-h)^2 + (y-k)^2 = r^2
where h = 4; k = 6, r=6
Answer (in standard form)= (x-4)^2 + (y-6)^2 = 36 
Answer (in general form)= x^2 + y^2 -8x -12y +16
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