Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions


[secx + tanx].[secx + tanx]= [1 + sinx]/1-sinx

secx=1/cosx; tanx = sinx/cosx;

[1/cosx + sinx/cosx].[1/cosx + sinx/cosx] =[1+sinx]/[1-sinx];

[cosx +sinxcosx]/cos^2x .[cosx +sinxcosx]/cos^2x;

[cosx[ 1 +sinx]/cos^2x]. [cos[1 +sinx]/cos^2x;

cancel x;

[1+sinx]/cosx. [1+sinx]/cosx=[1+sinx]/1-sinx;


hence: cos^2x= 1-sin^2x

[1+sinx][1+sinx]/1-sin^2x= [1+sinx]/1-sinx];


cancell : [1+sinx];


0 0 0
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts