Answers

2014-08-03T14:36:16+08:00
2m²-m^3
2m^3-3m²+2m-3

solution:  \frac{2m²-m^3}{2m^3-3m^2+2m-3}
= 2m^-1+3m+2m-3

final answer:  \frac{3m+2m-3}{2m}
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2014-08-03T14:54:53+08:00
(2m^2 - m - 3) / (2m^3 - 3m^2 + 2m - 3) (2m - 3)(m + 1) / (2m - 3)(m^2 + 1) *cancel similar terms (m + 1) / (m^2 + 1) *note : be careful not to cancel out m + 1 and m^2 + 1. m^2 +1 can be only expanded in the form of (m + i)(m - i) where i = sqrt -1
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