Answers

2014-08-05T15:12:35+08:00
Assuming that the first pool was a square, we use the equation: A = s^2, where A is the area of the square and s is the side of the square. We substitute the values, we get: 8 = s^2, s = sqrt 8 ~ 2.828 m. We compute the new area of the rectangle pool, Area = (2.828 + 2)(2.828 - 2) ~ 4.000
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