Answers

2014-08-08T14:47:05+08:00
2d/d-5 + 1/d-3 = 3
then
(d-5)(d-3)[(2d/d-5+1/d-3)] =  3(d-5)(d-3)        multiply the equation by( d-5)(d-3)
 2d(d-3)+ 1(d-5) =  3d²-24d+45
 2d²-5d-5 =     3d² -24d+45
=    d²-19d+50 = 0

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2014-08-09T04:18:47+08:00