Answers

2014-08-16T20:36:12+08:00
[(6^3)(x^3)(y^15)]^-1/3 = [6^(-3/3)][x^(-3/3)][y^(-15/3)] = [(6^-1)(x^-1)(y^-5)] = 1 / [6xy^5]
0
2014-08-16T23:22:48+08:00