# Sheryl bought a bag and a pair of shoes at the store. She paid 1,350 for bought items.If the pair of shoes cost 470 more than the bag, how much did each item cost?

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by alialfonso

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by alialfonso

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given: P1,350 , P470

operation:subtaction

solution: 1350

- 470

= 880

answer:the pair of shoes cost 470 and the bag was 880!!!!!!

im not really sure of my answer bec. you put MORE THAN THE BAG !

₱ 470 + x = cost of a pair of shoes.

where: x = bag

Sol'n:

x + (₱470 + x) = ₱ 1350.00

₱470 + 2x = ₱ 1350.00

2x =₱ 1350.00 - ₱470.00

2x = ₱880.00

2x / 2 = ₱880 /2

x = ₱440.00 (bag)

₱470 + x =? (pair of shoes)

₱470 + ₱440 = ₱910.00 (pair of shoes)

therefore: the x, which is the bag is ₱ 440.00 and the pair of shoes is ₱ 910.00

Checking:

bag + Pair of shoes = ₱1350.00

₱440.00 + ₱910.00 = ₱1350.00