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x-5 \sqrt{x} +4=0
We can do quadratic equation but the result would be the square root of x
 \frac{5±\sqrt{25-16} }{2} = \sqrt{x}
the possible values for the square root of x is either 4 or 1, we square the numbers 
so x is either 16 or 1
Please don't mind the A I can't seem to delete it