Answers

2014-03-02T15:45:31+08:00
The four consecutive numbers are 51, 53, 55, and 57..
solutions:
let these as the four consecutive no.s:
2n+1, 2n+3, 2n+5, 2n+7

then, substitute:
2(2n+1 + 2n+3) - (2n+5 + 2n+7)=96
8n+8-4n-12=96
n=25

substitute 25 to 2n+1, 2n+3, 2n+5,and 2n+7, and you will get 51, 53, 55, and 57.
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