Answers

2014-08-31T23:14:44+08:00
x^2+6x > -5\  \  | \ add\ 5\ to\ both\ sides \\\\x^2+6x+5>0 \\ \\(x^2+x)+(5x+5)>0 \\\\  x(x+1)+5(x+1)>0\\\\(x+1)(x+5)>0 \\ \\first\  we \ solve: \\(x+1)(x+5)=0\\x+1=0 \ \ or \ \ x+5=0\\x=-1 \ \ or \ \  x=-5

a  >  0 open for up . 

 So we know that the curve is u-shaped and that it crosses the x-axis at x=-1 and x=-5.

The curve is more than zero  :   -5< x < -1

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