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\small (x+2) (3x-4)=3x\cdot x-4x+2\cdot 3x-2\cdot 4=3x^2-4x+6x-8=3x^2 +2x-8

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(x+2)(3x-4) the answer is three x squared plus two x minus eight....im sorry if i write it in word b'cos i don't now how to put the number squared.....
ok :),
you have to subtract -4x and positive 6x because it dont have the same signs....
3x²-4x+6x-8 or 3x²+2x-8
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