Answers

2014-09-03T20:09:19+08:00
\small (x+2) (3x-4)=3x\cdot x-4x+2\cdot 3x-2\cdot 4=3x^2-4x+6x-8=3x^2 +2x-8


0
(x+2)(3x-4) the answer is three x squared plus two x minus eight....im sorry if i write it in word b'cos i don't now how to put the number squared.....
ok :),
3x^2-4x+6x-8
-4x+6x=2x
you have to subtract -4x and positive 6x because it dont have the same signs....
2014-09-03T20:30:43+08:00