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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let P the number of pool to be empty,S is speed,T is time P = S x T smaller pipe 's speed is S P=1, T =14 1 = S (14) S = 1/14 pool per hour bigger pipe's speed is S let x the time of the bigger pipe to empty a pool , P=1 1= S x S = 1/x pool per hour

together speed is (1/14) + (1/x) = (x/14x) + (14/14x) = (x+14)/14x pool per hour

back to the formula P = S x T where P = 1 , T = 7/2 (together time 3 1/2 hour) 1 = [(x+14)/14x] (7/2) manipulate the equation, 1 = (7x +98)/28x 28x = 7x + 98 28x -7x = 98 21x = 98 x = 98/21 x = 14/3 or 4 2/3 it takes 4 2/3 Hours to empty the pool by the bigger pipe alone