# Neglecting Friction; determine the horizontal force needed to accelerate a 25 kg grocery cost from rest to a velocity of 0.45 s in 1.35 s.

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by jennymae13

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by jennymae13

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where:

F=force

m=mass (25 kg)

a=acceleration= (velocity/time)= 0.45 m/s / 1.35 s = (1/3 m/s²)

*Substitute and Solve:

F=ma

F=(25 kg) × (1/3 m/s²)

F=25/3 kg m/s²

F= 8.33 Newtons

*Therefore, the horizontal force is 8.33 Newtons