Answers

2014-09-16T22:00:18+08:00
Identifying the given you'll have:
 the change of volume per time,
      dV/dt = 6cm/min
 the length of a side      
      s = 12cm
Volume of a cube, V = s^{2}
   differentiating it with time,
   \frac{dV}{dt} = 3s²  \frac{ds}{dt}
 substituting the values given:
  6 = 3(12)² \frac{ds}{dt}
 \frac{ds}{dt} = 0.0139 cm/min
0
*V=s^3
Are you able to understand how it's done?