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An object is thrown vertically upward with a

velocity of 96 m/sec. If the distance S(t) above the ground after t
seconds is given by the formula S(t)= 96t-5t²,a.)How high will it be at
the end of 3 seconds?
b.)How much time will it take the object to be 172 m
above the ground?
c.)How long will it take the object to reach the highest
point? What is the maximum height reached?



t=d/s t=172m/96t t=1.79166667 or 1.7917
3 3 3
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