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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let x be the first number x+1 be the 2nd number x+2 be the 3rd number as stated in the problem, we can form the equation: (x+1)² + (x+2)² = x² + 21 expanding the terms we'll have (x² + 2x + 1) + (x² + 4x +4) = x² + 21 combine the like terms and transposing x² + 21 to the left: x²+x²-x² + 2x + 4x +1 + 4 - 21 = 0 x² + 6x -16 = 0 factor: (x + 8) (x - 2) = 0 getting the roots: x + 8 = 0 x = - 8 x - 2 = 0 x = 2 taking the first value of x which is -8, the consecutive negative integers would be: x = -8 x + 1 = -7 x + 2= -6 (-8,-7,-6) considering the second value of x which is 2 the consecutive positive integers would be: x= 2 x + 1 = 3 x + 2 = 4 (2,3,4)