Jake has twice as many books as Bob. Pete has B more books than Bob Bob has B books. How many books do the three boys have althogether in terms of B ?

2
by lan

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Jake has twice as many books as Bob. Pete has B more books than Bob Bob has B books. How many books do the three boys have althogether in terms of B ?

2
by lan

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They would have b^2 + 3b. Solution?

B*2 = b^2

b + b = 2b

2b + b = 3b

= b^2 + 3b

B*2 = b^2

b + b = 2b

2b + b = 3b

= b^2 + 3b

Since it is said that Jake has twice the number of books Bob has, we can say that Jake has a number of books given by 2B.

Pete has B more books than Bob has, which can be said as B+B, which is also 2B.

For simplicity:

B=Bob books

2B=Jake books

2B=Pete books

Therefore, if we add Bob's, Jake's and Pete's books, we get:

B+2B+2B=5B

Hope that helps.