Answers

2014-10-04T11:59:30+08:00
First you need to know the number of moles of 5.76 x 10 x^{22} by divding it to avogadro's number (6.022x10 x^{23} )

5.76 x 10^{22} molecules   x     \frac{1mole}{6.022 x 10^{23}molecules }
= 0.09 mole

find the molar mass of ammonia
N + 3H = molar mass of ammonia
(14.01) + (3)(1.008) = 17.034 g/mol

now, multiply 0.09 mole to 17.034 g/mol

0.09 mole NH_{3}  x  \frac{17.034grams}{1 mole NH_{3} }
= 1.53306 grams 
0
the formula is 6.o2X10 expo 23
yes, i just forgot to remove the x there. But you can see that it is right on the solution.
ok tnx :)