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Fuller’s car is 4 metres long. This is the average length of all 4 cars at the
surgery. A parking bay has to be marked out along the roadside. If an extra
1.5m gap is allowed for each car to drive into the space, how long does the bay
have to be for all the cars to be parked?

27m 17m 20m 24m 30m


Well I think the answer is  20 m long because as you said there are 4 cars and it includes Dr. Fuller's because u said all. so 4 (cars) times 4 m plus 4 times 1.50 for each gap. so the equation is x= 4(4)+4(1.5) = 20m

am I right? I hope so

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