Answers

2014-03-25T23:15:00+08:00
The equation of the circle is given by:
4 x^{2} +4 y^{2} -7x+6y-35=0


We could transform this to its general form (x-h)^2+(y-k)^2=r^2 by manipulating the equation. (Mostly by completing a square.)

Rearranging the equation to easily see like terms, we get:
4x^2 -7x +4y^2 +6y -35=0

Using the techniques of completing the square, we will have:
(4x^2-7x+ \frac{49}{16}) - \frac{49}{16} +(4y^2+6y+\frac{3}{2}) -\frac{3}{2} -35=0

Rearranging:
(4x^2-7x+ \frac{49}{16})+(4y^2+6y+ \frac{9}{4})  =  \frac{49}{16} + \frac{9}{4}+35

Combining:
(2x+ \frac{7}{4})^2 +(2x+ \frac{3}{2})^2= (\frac{ \sqrt{645} }{4} )^2

Now, since we have the general equation and we know the value of r, which is  \frac{ \sqrt{645} }{4} , we use the formula of getting the area of a circle in terms of r. 

Area= πr^2

Therefore the area is:
\frac{645 \pi }{16}

Hope that helps.

If you still have any problems and/or if there are any errors in this answer please post a comment on my profile or message me. Thanks!
0