Answers

2014-10-10T01:33:25+08:00
Since this involves combination where there are 2003 people and 2000 people to be selected then we'll have it done using the combination formula taken to be as:
C = S =  \frac{P}{r!}
 _{2003} C  _{2000} = \frac{2003(2002)(2001)(2000)...(4)}{2000!}
 _{2003} C  _{2000} = 1,337,337,001 combinations
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