Answers

2014-04-04T17:46:55+08:00
Using the formula Sn = n/2(2a + (n-1)d)
Sn = sum of the series
n = how  many terms
a = first term
d common difference
95 = 5/2(2a+(5-1)1)
95 = 5/2(2a+4)
95 = 10a/2 + 20/2
95 = 5a + 10
5a = 95-10
a = 85/5
a = 17
Now you can count up to the third number which is 19 or use formula
an = a+(n-1)d
where n = 3
an = 17+(3-1)1
an = 17+2
an = 19
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2014-04-05T07:54:11+08:00
X+x+1+x+2+x+3+x+4=95 5x +10=95 X=17 Third number, x+2 17+2 =19
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