# A committee of 6 is to be selected from 6 lawyers and 9 engineers. In how many ways can 2 lawyers and 4 engineers be chosen to form the committee? 3 lawyers and 3 engineers?6 engineers? all lawyers?

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by fontana

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by fontana

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for 2 lawyers and 4 engrs you will have:

for 2 lawyers taken from 6lawyers

for 9 engrs taken 4

multiply the two results to find the answer. you'll have:

or in the calculator, you just have to input,

for the next question - 3 lawyers, 3 engrs

for 6 engineers:

all lawyers: