Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Can you help me find the correct answer para po sa mixture problem? ito po ang problem: "drew, a chemistry student, wanted to take experiments with an

available solution of 70% and 40% alcohol. he was instructed to prepare a 150 ml solution with 60% alcohol mixing from each other. how much solution should he use?" i got the value of y as 15 and x as135. is this the correct answer?? help me please!! thanks a lot..:)

Let 'x' be the amount with 70% alcohol 'y' be the amount with 40% alcohol you're given that the resulting solution must be 60% concentrated and that the total amount would be 150ml. from there we can say that x + y = 150 ------let this be equation 1 in getting the desired concentration, you'll have the equation as: 0.70x + 0.40y = 0.60(150) -----equation 2 from equation 1, we can get the value of x in terms of y x + y = 150 x = 150 - y -----equation 3 substitute equation 3 to 2 0.70x + 0.40y = 0.60(150) 0.70(150 - y) + 0.40y = 90 105 - 0.70y + 0.40y = 90 -0.70y + 0.40y = 90 - 105 -0.30y = -15 y = 50ml substituting the value of y in equation 3 x = 150 - y x = 150 - 50 x = 100ml