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## Answers

__Using elimination method:__

4x - 5y = -8 ----equation 1

-x + 3y = 2 -----equation 2

multiply equation 2 with 4

(-x + 3y = 2) x 4

-4x + 12y = 8 ----equation 2'

add equations 2' and 1

-4x + 12y = 8

+ 4x - 5y = -8

7y = 0

y =0

multiply equation 1 with 3 and equation 2 with 5

(4x - 5y = -8) x 3

(-x + 3y = 2) x 5

12x -15y = -24

-5x +15y= 10

add both equations

7x = -14

x = -2

Using substitution method:

4x - 5y = -8 ----equation 1

-x + 3y = 2 -----equation 2

rearranging equation 2 you'll have:

-x + 3y = 2

x = 3y -2 ----equation 3

substitute equation 3 to equation 1

4x - 5y = -8

4(3y - 2) - 5y = -8

12y - 8 - 5y = -8

7y = -8 + 8

7y = 0

y = 0

substituting the value of y to equation 3 you'll have

x = 3y - 2

x = 3(0) - 2

x = -2