Note that just before overtaking, train 'A' is having the same distance as the car that chased it.

remember that v = d/t or d = vt

where v is the velocity or speed

d is the distance

t is the time

for the train you'll have the distance as:

d = vt

take note that the train traveled (@7am) 1 hour ahead so,

d = 40(t +1)

d = 40t + 40 ----equation 1

for the distance traveled by the car you'll have

d = vt

d = 80t ---equation 2

remember that both the train and the car traveled the same distance from the station so you can equate the distance(equation 1 and 2) and you'll have it as:

40t + 40 = 80t

40 = 80t - 40t

40 = 40t

__t = 1hour__

since the time is 1 hour, then it is 1 hour after the car leaves the station.

remember that the car leaves the station 1 hour after the train left. so the car left the station @8am.. since the time traveled by the car is 1hr just before overtaking, then the car overtook the train 1 hour after leaving the station or that would be 2 hours from the time the train left and it would be at __9am.__