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Put it in the form of y = a(x - h)^2 + k
by doing so, you'll know that the vertex is at (h,k)

OR put it in the form of y = ax^2 + bx + c and get the vertex through(-b/2a, (4ac - b^2)/4a)

if a>0, the parabola is facing upwards. if a<0, it is facing downwards

look for its x-intercepts. let y = 0, and solve for x. plot the points. connect.

0 0 0
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